BECE Mathematics — Area of Triangle Past Questions & Answers

Question 1

The shaded segment is a piece of land cut from the plot in the form of a quadrant ABCD with a radius of Calculate the area of the shaded portion, correct to [Use π = 22/7, Area of a Quadrant = 1/4πr², Area of = ½ x base x height]

Accepted Answer

A: 120m²

Answer

B: 182m²

Answer

C: 114.3m²

Answer

D: 392m²

Question 2

The structure below shows two strings /AP/ and /BP/ measuring 5m and 4m holds a street electricity pole, /PC/. Given that /AB/ = /BC/, calculate the height of the pole, given that the area of ∆PAC = 27m².

Question 3

Calculate the area of the shaded portion, given that the area of a sector is 314.2857 cm^2 and the area of a triangle is 200 cm^2.

Answer

C: 114.28m^2

Question 4

P Area of ΔPAC = Let PC = H (height) AB = BC = x Area = 1/2bh 27 = 1/2 x 2x x h xh = 27 --- (i) by pythagoras' theorem 4^2 = x^2 + h^2 --- (ii) C 5^2 = (2x)^2 + h^2 25 = 4x^2 + h^2 --- (iii) Subtracting (ii) from (iii) 25 = 4x^2 + h^2 -16 = x^2 + h^2 9 = 3x^2 x^2 = 9/3 x^2 = 3 x = √3 Put x^2 = 3 in equ. (ii) 16 = x^2 + h^2 16 = 3 + h^2 16-3 = h^2 h^2 = 13 h = √13 = 3.6 m or Put x = √3 in equ. (i) xh = 27 √3h = 27 h = 27/√3 h = 9√3 = 15.5m

Question 5

P Q R 9cm 10cm 25° Area of triangle = 1/2 bh sin = 1/2 x 9cm x 10cm x sin 25 = 1/2 x 90 x 0.4226 = 19.017 cm².

BECE Mathematics — Area of Triangle Past Questions & Answers

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